Lets not try to get to technical here, I’ve read every description of why HHO works to save gasoline I can find. Some explanations can get mind boggling, and others a high school chemistry student can prove right or wrong. So here is my explanation and theory, added to all the others for you to decide.
Gasoline burns in the engine with about a 15:1 air ratio, 15 parts air, 1 part fuel
The gas engine is basically inefficient, only about 20-30% efficient, and thus releases massive amounts of heat and wasted fuel.
Introduce HHO, a combination of Oxygen and Hydrogen, ready to burn, in the correct ratio, and only produces water, power and heat.
The HHO replaces gas and air, that the engine requires, when gasoline is replaced by HHO, fuel mileage goes up. You dont need more air, the proper mix is already there, you need less gasoline.
As a byproduct the gasoline is burned more completely, burning the heavier parts, the nanocanes, the dodocanes, the octanes, etc., making a cleaner engine, wasting less fuel. Hydrogen has about 3 times the energy of gasoline and thus replaces about 3 parts of gasoline for each part of HHO used.
I have begun to suspect that the Hydrogen or Oxygen, or both possible break down the heavier hydrocarbons into lighter ones. The lighter ones burn more efficiently, like pentane, propane and methane, thus utilizing more of the available power.
A fact that cant be overlooked, is that the oxygen sensors have to be adjusted (hacked) to prevent the cars ‘brain’ from adding more gas because of the higher sensed oxygen levels. We’re adding more oxygen with the HHO, to the air intake, the car doesn’t sense the more fuel, only the oxygen. It turns out there are also O2 sensor extenders that will prevent the rich state from more oxygen by moving the O2 sensor further from the exhaust flow (only for exhaust O2 sensors).
Gasohol, look at that same chart, mix gas with ethanol, methanol, etc which all have less energy per unit, and the gasoline energy goes down! Does this mean there’s less energy per gallon of fuel, at the same low efficiency conversion, for the car? And we pay more for the fuel! But, again the fuel does contain some of its own oxygen for burning, so mileage apparently stays about the same, but cleans up the burning.
You’ll also notice in the same chart, that the octane number is higher, so that it is roughly equivalent to running on the alcohol and methanol. So that tells me that as the levels of HHO are increased to 10% or more of the fuel needed, the timing will have to be changed to compensate, and eliminate harmful pinging.
Ideally, the engine would draw pure HHO, for whatever engine speed, in the correct amount, with no additional air. The additional air would prevent combustion, and/or run so lean as to melt down the engine.
So for now, replacing a portion of the intake air, with a perfect mix of fuel and air, reduces the amount of gasoline needed by the engine, provided you adjust the O2 sensors. If you have an older car (before O2 sensors) you don’t have that problem.
How high can that mix can be? You tell us, what is your conversion saving in fuel? and how much HHO are you producing? Does the engine temp go up at idle? What size engine are you using? I feel a federal research grant being issued right now! Can we actually do the research ourselves?
Filed under: How HHO works | Tagged: gasohol, hho, hho air ratio, hho energy, hho fuel, o2 sensor, octane number, why hho works | 34 Comments »